f ,g are defined around x0 for which lim fg(x)=infinity when x->x0 . prove that if k>0 so f>g>0 for every x on |x-x0|<k then lim f(x)=infinity when x->x0 . i tried: for every n>0 every x in |x-x0|<k makes fg>N what now?
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If g goes to infinity and f> g, then f goes to infinity. If neither f nor g goes to infinity, then fg does not.
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