f ,g are defined around x0 for which lim fg(x)=infinity when x->x0 .

prove that if k>0 so f>g>0 for every x on |x-x0|<k then

lim f(x)=infinity when x->x0 .

i tried:

for every n>0

every x in |x-x0|<k

makes fg>N

what now?

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- Nov 14th 2010, 02:12 PMtransgalacticprove by limit definition
f ,g are defined around x0 for which lim fg(x)=infinity when x->x0 .

prove that if k>0 so f>g>0 for every x on |x-x0|<k then

lim f(x)=infinity when x->x0 .

i tried:

for every n>0

every x in |x-x0|<k

makes fg>N

what now? - Nov 15th 2010, 04:41 AMHallsofIvy
If g goes to infinity and f> g, then f goes to infinity. If

**neither**f nor g goes to infinity, then fg does not.