Determine the equation of a function to the type y=ax^2 + bx + c given that the curve is tangent to the linke y = x+4 when x = -1 and tangent to the line y = 11x + 10 when x =2

cheers for any help :)

Printable View

- November 14th 2010, 01:34 AMTarik678equation to tangent.
Determine the equation of a function to the type y=ax^2 + bx + c given that the curve is tangent to the linke y = x+4 when x = -1 and tangent to the line y = 11x + 10 when x =2

cheers for any help :) - November 14th 2010, 02:27 AMUnknown008
1. Get the derivative of the curve.

2. From the equation of the first tangent, we know that the gradient of the curve at x = -1 is 1.

So, in your derivative, plug in x = -1 and equate to 1.

3. So the same thing with the second tangent.

4. Solve the equations, that you just obtained, simultaneously to get the values of a and b for your original curve.