Remember that the transformation from cartesians to polars is .
So your double integral should be
.
You can solve this using a substitution.
Hi all,
I need help with the following task:
Calculate
∫∫ ln(1+x^2+y^2) dxdy
D
where D is: (x,y); 1 <=x^2+y^2<=2
(<= means bigger than or equal to)
I think I should use polar coordinates where
x= r cos §
y= r sin §
Then I get:
∫∫ ln(1+r^2)
∫ dr goes from 1 to 2
∫ d§ goes from 0 to 2 pi
But what is the integral of ln(1+r^2)?
I really need help,
thanks!