Find the point in the first quadrant lying on the parabola y = 1 - x^2 such that the tangent line to the parabola at this point and the coordinate axes cut out the triangle with the smallest area.
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First step: If $\displaystyle (x,y)$ is a point on the parabola, find the equation of the tangent line. Solution: $\displaystyle 2xX+Y=1+x^2$. Regards.
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