Throw that calculator out
Go to this web site
Hi there, i am having problems evaluating
which is differentiated to...
when
when i put the numbers in i get the wrong answer, can someone explain what i am doing wrong, also im not sure what to do with the sec^2, how do you work this out on a calculator (for future reference) ???
Many thanks
Throw that calculator out
Go to this web site
With all do respect, I must tell you some simple facts.
If you do not know the very basic relationships among the trig functions, there is absolutely no reason for you to even bother with these problems. We can of course tell you the answer. But what good does that do for you?
If you do not understand why implies that then you are wasting your own time.
Since , is its own conjugate and . Since, for any angle , , . From that so . From that,
.
Or: because , there exist a right triangle with both acute angles equal to . Because the two angles are the same, so are the legs. Take them to have length "1". Then, by the Pythagorean theorem, the length of the hypotenuse is given by so that . = "near side over hypotenuse"= [/tex]\frac{1}{\sqrt{2}}[/tex] so that .
To do that on a calculator, first make sure you calculator is in radian mode, then enter "pi" "/" "4", press the "cosine" key, then the reciprocal, "1/x" key.
Its ok, i got it wrong...
i have followed this up on this page; http://www.mathhelpforum.com/math-he...on-163024.html