# Math Help - Absolute Extrema in a region (Calc 3)

1. ## Absolute Extrema in a region (Calc 3)

$

f(x,y)=x^4 - 4x^2y^2 + y^4

in the region (x,y): -1<=x<=1 -1<=y<=1
$

so far i found the critical points to be (0,0) and (1/2,1/2)

im stuck trying to find points on the four bounded segments

2. Just examine these four cases: x=-1, x=1, y=-1, y=1.

For example,
x=-1
f(-1,y)=1-4y^2 + y^4
df(-1,y)/dy = 4y^3 -8y
Equate this to 0 and solve for y.
4y(y^2 - 2)=0
y=0, y=sqrt(2) [Ignore, since it is outside the region]

Do these for all cases, and also check the endpoints (-1,1), (-1,-1), (1,1), (1,-1)

Of all these values, find out which one is the highest and the lowest.