Here is my original problem:

$\displaystyle \displaystyle\int\frac{(1+x)^2}{\sqrt{x}} dx$

Here are the steps I worked. I'm VERY new to integrals and substitution, so bear with me, please.

$\displaystyle u = (1+x)$ ; $\displaystyle du=dx$ ; $\displaystyle x=u-1$

$\displaystyle \displaystyle\int u^2(x)^{\frac{-1}{2}}du$

$\displaystyle \displaystyle\int u^2(u-1)^{\frac{-1}{2}}du$

Am I on the right track so far? Multiplying the $\displaystyle u^2$ with the $\displaystyle (u-1)^{\frac{-1}{2}}$ is kinda throwing me off...should that be what I do next? If so, as a result of that multiplication, I am getting $\displaystyle u^{\frac{3}{2}}-u^2$ which I think is wrong. I don't mean this to be rude but if you want to help me, pleasedontwork the problem for me, I just want to be pointed in the correct direction. I learn better when I can work it out myself. Thanks