y=x^6 with the intervals 0≤x≤1
how do i setup this integral for the area of the surface obtained by rotating the curve about the y-axis??
i dont get it at all.. i understood how to rotate it about the x-axis which i got integral from [0,1] of int(2πx^6sqrt[1+(6x^5)^2])
but i dont know how ot set it up for the y-axis?
"thickness" is relative. see for yourself ...
PlanetMath: area of surface of revolution