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Simple observation will show that is a solution.
Hi. I have a maths question on finding the turning points and determining their nature but I can't find the value of x and w.
The equation is z= e^(2x) + e^(-y) + e^(w^2) - e^(ln2x) - 2e^(w) + y
I differentiated it wrt to x, y and w.
But I can't solve for x and w in the following equations:
2e^(2x) - [ (e^ln2x) / x) = 0
2we^(w^2) - 2e^(w) = 0
I really need help for this one. Thanks.
I did what you did but it's not right. x cannot be equal to 0, otherwise if you replace it in 2e^(2x) - [ (e^ln2x) / x) = 0,
(e^ln2x) / 0 will be undefined and I need a value of x. And for the second equation how would I know if w has only one value and not 2?
Yes, you are right, if you leave the function written as is. You can simplify your original function though, because . Otherwise the function will be not be defined for any nonpositive value anyway...
In the second case, you would need to show that does not have any turning points.