There is a mistake:
The tangent line is:
The parametric form of the tangent line to the image of f(t)=2t^24/tt−5 at t=−1 is ?
I got the normal vector to the tangent, <4t,4/t^2, 1>.
Should I plug in the t=-1 to the original equation to find a point, then plug in t=-1, into the tangent line equation as well?