Thread: Another Vector Problem

The parametric form of the tangent line to the image of f(t)=2t^24/tt−5 at t=−1 is ?


I got the normal vector to the tangent, <4t,4/t^2, 1>.

Should I plug in the t=-1 to the original equation to find a point, then plug in t=-1, into the tangent line equation as well?

Thanks!

There is a mistake:

and so,

The tangent line is:



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Fernando Revilla

Oh duh!


So I get,

<-4t,-4-4t,t-6>