The parametric form of the tangent line to the image of f(t)=http://omega.math.union.edu/webwork2...144/char0A.png2t^2http://omega.math.union.edu/webwork2...144/char3B.png4/thttp://omega.math.union.edu/webwork2...144/char3B.pngt−5http://omega.math.union.edu/webwork2...144/char0B.png at t=−1 is ?

I got the normal vector to the tangent, <4t,4/t^2, 1>.

Should I plug in the t=-1 to the original equation to find a point, then plug in t=-1, into the tangent line equation as well?

Thanks!