This is incorrect. Dividing both numerator and denominator of by gives . And, now, unfortunately, that is NOT the same as [/tex]\frac{1}{1+ x^2}[/tex].
Perhaps dividing both numerator and denominator by giving so we can think of it as a Riemann sum for will work.
To what familiar and very easy to integrate function's Riemann sum does the last sum above ressemble?
And in what interval, of course?
Tonio