Thread: Use differentials to estimate the value of 30^(1/5)

i know you need to find a nice number that would solve out but the only one i could find was 5 so 5^1/5 = 1. but when i try to put that value into the derivative (1/5)(5^-4/5) i get some random number so i must be doing something wrong! help??

Originally Posted by yess

i know you need to find a nice number that would solve out but the only one i could find was 5 so 5^1/5 = 1. but when i try to put that value into the derivative (1/5)(5^-4/5) i get some random number so i must be doing something wrong! help??

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Take , x = 32, h = -2.

Or, you could just use the Binomial expansion.

and so on.