Hopefully you can read my writing!
OK so this was a bigger integral at first, but i got it down to that with some substitution with u.
Now im stuck at the part with the brackets, where i need to do integration by parts on reverse chain rule and im not sure how to do that, for example i took
v = (x1 - (x1/u))^alpha3 -1
i found dv,
then i set:
dt = (1-(x1/u))^alpha2 - 1 du
I'm not sure how to get t here, i tried using substitution where:
m = (1-(x1/u)), then i found du = ((u^2)/x1) dm, and i tried subbing that in so i had to find the anti-derivative of:
m^alpha - 1 * (u^2/x1) dm
i don't know if this is right or not if anyone can help because i don't think my answer is right.
So thats a statistics question but in order to solve that i need to set up a double integral such that the entire function equates to 1. The gamma equation at the start is a constant and my prof told me to use the substitution u = x1/1-x2. I pulled out the constant.