4/243Log(3x-2)-4/243log(3x+2)
Maybe start by taking out a common factor here
$\displaystyle \frac{4}{243}\log (3x-2)-\frac{4}{243}\log (3x+2)$
$\displaystyle \frac{4}{243}\left(\log (3x-2)-\log (3x+2)\right)$
$\displaystyle \frac{4}{243}\left(\log \frac{(3x-2)}{(3x+2)}\right)$
Depending on what you want to do next you can now use the change of base formula mentioned in post #2. What base is your logarithm?