Find the rate at which the volume of a sphere is changing with respect to its radius. $\displaystyle V = (4/3)pi*r$ Any help is appreciated. Thanks.
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Originally Posted by lancelot854 Find the rate at which the volume of a sphere is changing with respect to its radius. $\displaystyle V = (4/3)pi*r$ Any help is appreciated. Thanks. You need to take the derivative with respect to r Note your formula for the volume of a sphere is incorrect $\displaystyle \displaystyle V=\frac{4}{3} \pi r^3 $
Oh, I must of written the formula down wrong. xD Does this first step look correct? $\displaystyle \frac{dv}{dx} = \frac{4}{3} \pi 3r^2 \frac{dr}{dx}$
Originally Posted by lancelot854 Oh, I must of written the formula down wrong. xD Does this first step look correct? $\displaystyle \frac{dv}{dx} = \frac{4}{3} \pi 3r^2 \frac{dr}{dx}$ where did the variable $\displaystyle x$ come from ? the problem statement says to take the derivative w/respect to the radius ... $\displaystyle \displaystyle \frac{dV}{dr} = 4\pi r^2$ you're done.
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