Yes, although you need to use the chain rule three times because of the sin function
Set and so that
By the chain rule:
Question: y=3Sin^4(2x)
...how do you solve this using the chain rule;
dy/dx= dy/du X du/dx,
y =3Sin^4 where u = 2x <<<< is this correct?
what do i do after this, can someone explain
i think im using differentiation rules;
sin x = cos x
x^n = nx ^n-1
No, I don't know where your 3 has gone?
Your individual differentation is fine, apart from dy/dv which is 12v^3 (you didn't multiply by that 4)
When we put in our original substitutions back we get: