Evaluate the limit using L'Hospital's rule.

y = lim x->infinity (5x-1/5x+3)^5x+2

$\displaystyle ln y = (5x + 2) ln (5x-1/5x+3)$

$\displaystyle lim x-> infinity$ lny= lim x-> infinity ln (5x-1)-ln (5x+3)/ 1/(5x+2)= lim x-> infinity 5/(5x − 1) − 5/(5x + 3)/−5/(5x + 2)^2

I'm not sure how to proceed after this step.

Any help would be appreciated, thank you for your time and effort :D