I am unable to solve these problems:- differentiate :1. sin^-1(tan x) 2.tan^-1(sin x)
Last edited by Masiullah; Jun 25th 2007 at 01:22 AM. Reason: new problem
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differentiate: $\displaystyle d(\sin^{-1}u) = \frac{1}{\sqrt{1-u^2}}du$ $\displaystyle d(\sin^{-1}(3x-4x^3))$ $\displaystyle =\frac{1}{\sqrt{1-(3x-4x^3)^2}}d(3x-4x^3)$ $\displaystyle =\frac{3-12x^2}{\sqrt{1-(3x-4x^3)^2}}$
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