Prove that the second derivative of the Logistics equation: A=A(max)/1+Ce^-kt is given by A''=A(max)Ck^2e^-kt(Ce^-kt-1)/(1+Ce^-kt)^3 Any help would be greatly appreciated
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$\displaystyle A= A_{max}(1+ Ce^{-kt})^{-1}$ Can you find the first derivative?
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