1. ## Have I gotten to the correct answer?

Hi guys, I'm doing chain rule problems to practice for exam:

I've encountered: y = (e^u - e^-u)/(e^u + e^-u)

I've gotten: dy/du = 4/(e^u + e^-u)^2

Is this the correct simplified answer? Thanks for the look!

2. Originally Posted by DannyMath
Hi guys, I'm doing chain rule problems to practice for exam:

I've encountered: y = (e^u - e^-u)/(e^u + e^-u)

I've gotten: dy/du = 4/(e^u + e^-u)^2

Is this the correct simplified answer? Thanks for the look!

Be sure you understand the following algebraic simplifications:

$y=\frac{e^u - e^{-u}}{e^u + e^{-u}}=1-\frac{2e^{-u}}{e^u+e^{-u}}=1-\frac{2}{e^{2u}+1}$ , and deriving now this is much simpler:

$y'=\frac{4e^{2u}}{(e^{2u}+1)^2}$ . Check now that this is just what you got...