How Do U Find The Tangent Of This??

i really don't understand what to do...

it says to determine the equation of the tangen to the curve

y= 1/x at the point on the curve where x=2 ?????

and then the following question is like to find the equation of the tangent to y=x^2 -2y+5=0 which is perpendicular to the line x-2y+5=0

????? how do u do it wen u hav to hav find it perpendicular to that

Please Tell Me If Im Doing This Right Or Not

so u said to take the derivative and plug the number in...and then use the slope formula....please tell me im doing it the right way

y= x^-1

y'= -x^-2

f'(2)= -(2)^-2

=-1/4

m=(y2-y1)/(x2-x1)

m=(-1/4 - y)/(2-x)

m*(2-1)=(-1/4 - y)

what do i do from here?