# Sequence Convergence question

• November 2nd 2010, 05:21 PM
ihatemath
Sequence Convergence question
Determine if the sequence {(2n-1)/(3n^2+1)} n=1,2,3.... converges or diverges. If the sequence converges find its limit.

I did L'Hopital's rule to find the limit which I found to be 2/infinity= 0. Is this correct? Would that mean that the sequence converges. Would this also mean that the limit is 0?

• November 2nd 2010, 06:33 PM
skeeter
Quote:

Originally Posted by ihatemath
Determine if the sequence {(2n-1)/(3n^2+1)} n=1,2,3.... converges or diverges. If the sequence converges find its limit.

I did L'Hopital's rule to find the limit which I found to be 2/infinity= 0. Is this correct? Would that mean that the sequence converges. Would this also mean that the limit is 0?

$\displaystyle \lim_{n \to \infty} \frac{2n-1}{3n^2+1} = 0$