# Don't know how to do this improper integral?

• Nov 1st 2010, 03:11 PM
elpermic
Don't know how to do this improper integral?
The integral is 25/(x^2+27x+26) with limits of integration [0, ]

I know that this integral is going to be convergent.. I just don't know how to solve for the integral
• Nov 1st 2010, 03:27 PM
Plato
$\dfrac{25}{x^2+26x+27}=\dfrac{1}{x+1}-\dfrac{1}{x+26}$
• Nov 2nd 2010, 05:07 AM
HallsofIvy
Slight typo in Plato's post:
$\frac{25}{x^2+ 27x+ 26}= \frac{1}{x+1}-\frac{1}{x+ 26}$.