The area under the curve y= sin x, between x =0 and x = π

Show that the volume of the solid formed by rotating this area through 360 about the x-axis is exactly ½(π^2)

This is what I have after doing some of the work:

V = π (-cos^2x) limits π and 0

I am not sure how to take it any further to obtain the answer. Please help me out guys...