lim x --> 0 ((1-cos x)/ x^2)

How would I go about calculating this limit?

Thankyou

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- November 1st 2010, 04:36 AMkatedew987Calculating a Limit
lim x --> 0 ((1-cos x)/ x^2)

How would I go about calculating this limit?

Thankyou - November 1st 2010, 04:48 AMUnknown008
Maybe you can use the l'Hopital's rule twice.

That is, you differentiate the numerator and denominator with respect to x twice. - November 1st 2010, 04:51 AMkatedew987
Unfortunately, we're not yet allowed to use that rule. At this stage we're only supposed to be assuming that lim x--> sin x/ x = 1 and lim x--> 0 (1- cos x)/ x = 0. Thankyou for the input anyway though!

- November 1st 2010, 06:03 AMharish21
- November 1st 2010, 06:06 AMkatedew987
No, sorry, perhaps I didn't make it clear enough, I'm supposed to be finding lim x--> 0 ((1-cosx)/ x^2) working on the assumption that lim x--> (1 - cos x) = 0

- November 1st 2010, 02:53 PMhjortur
How did you do the original proof that

? - November 1st 2010, 03:02 PMAlso sprach Zarathustra
Use

And use:

YOU will get that the limit is 1/2 - November 1st 2010, 03:08 PMDrexel28
- November 1st 2010, 03:16 PMchisigma