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Math Help - Work Problem?

  1. #1
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    Work Problem?

    A force of 7 pounds is required to hold a spring stretched 6 in. beyond its natural length. How much work is done in stretching the spring from its natural length to 8 in. beyond its natural length? I know work=Integral(kx). I've tried all the way I know how..I know you change the bounds to feet (Bounds are 0 to 2/3 ft.) , because work is in Ft-lbs. I need the number for K.

    Do I use W=F*D, and plug in the work of 7lbs?
    Not really sure where to go, and I have a test on this tomorrow.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Bracketology View Post
    A force of 7 pounds is required to hold a spring stretched 6 in. beyond its natural length. How much work is done in stretching the spring from its natural length to 8 in. beyond its natural length? I know work=Integral(kx). I've tried all the way I know how..I know you change the bounds to feet, because work is in Ft-lbs. I need the number for K.

    Do I use W=F*D, and plug in the work of 7lbs?
    Not really sure where to go, and I have a test on this tomorrow.
    you begin by using Hooke's law: F = kx, F is the force needed to stretch the spring x feet from its natural length. k is the spring constant. it is the same k in the integral formula for work.

    can you continue now?
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  3. #3
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    Yes! Thanks. I didn't have that formula written down.
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