I am really confused on how to differentiate things like this.. please help. 6y^3 + 5xsiny = cos3x find dy/dx.
Follow Math Help Forum on Facebook and Google+
Originally Posted by mmfoxall I am really confused on how to differentiate things like this.. please help. 6y^3 + 5xsiny = cos3x find dy/dx. $\displaystyle \displaystyle 18y^2 \cdot \frac{dy}{dx} + 5x \cdot \cos{y} \cdot \frac{dy}{dx} + 5\sin{y} = -3\sin(3x)$ solve for $\displaystyle \displaystyle \frac{dy}{dx}$
What i get is [-3sin(3x) - 5sin(y)]/[(18y^2 + 5xcos(y)]. Is this right?
Originally Posted by mmfoxall What i get is [-3sin(3x) - 5sin(y)]/[(18y^2 + 5xcos(y)]. Is this right? Correct!
View Tag Cloud