Hi, how come when I integrate $\displaystyle 5/sqrtx$ the correct answer is $\displaystyle 10(sqrtx) + C$ I get $\displaystyle 5(sqrtx) + C$ ?
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$\displaystyle \dfrac{5}{\sqrt{x}} = 5x^{-1/2}$ When integrating add one to the power and divide by the new power - Remember that dividing by 1/2 is the same as multiplying by 2.
Originally Posted by e^(i*pi) $\displaystyle \dfrac{5}{\sqrt{x}} = 5x^{-1/2}$ When integrating add one to the power and divide by the new power - Remember that dividing by 1/2 is the same as multiplying by 2. Thanks I understand now!
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