Derivative of sec(cosx)

**Vamz** · October 30th 2010, 02:12 PM

$\displaystyle \frac{d}{dx} \sec ( \cos x ) =$

What am I doing wrong here?
f(x)=sec(U)
f'(x)='sec(U)*'U
f'(x)= $\displaystyle{\sec\!\left(x\right)\tan\!\left(x\ri ght)\cos\!\left(x\right)\!\left(-\left(\sin\!\left(x\right)\right)\right)}$

**Also sprach Zarathustra** · October 30th 2010, 02:25 PM

second line...

f'(x)=sec(U)tan(U)*dU/dx

U=cos(x)

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