If a line has equation
the parametric form is
Te parametric form for the tangent line to the graph of y = 2x^(2)+2x-1 at x = -1 is
Ok, So I got the slope at x=-1, which is -2. Then I found a points along the line, (-1,-1).
So I have the slope of the tangent line, y= -2x-3.
How do I translate this into parametric form?
Thanks