Integration problem.

**Frggr** · October 27th 2010, 04:57 PM

Lost as to how to do this.
Its not apparent if "Integration by parts" will work, or any substitutions. ((Came across this while working on differential equation problems, and half remembering learning how to do it before. So was hoping it wasn't too difficult))
$integral(2^xsinx)$

**pickslides** · October 27th 2010, 05:04 PM

Originally Posted by Frggr

Lost as to how to do this.
Its not apparent if "Integration by parts" will work, or any substitutions. ((Came across this while working on differential equation problems, and half remembering learning how to do it before. So was hoping it wasn't too difficult))
$integral(2^xsinx)$

Did you try doing it by parts twice?

**skeeter** · October 27th 2010, 05:06 PM

Originally Posted by Frggr

Lost as to how to do this.
Its not apparent if "Integration by parts" will work, or any substitutions. ((Came across this while working on differential equation problems, and half remembering learning how to do it before. So was hoping it wasn't too difficult))
$integral(2^xsinx)$

integration by parts ...

let $u = \sin{x}$ , $dv = 2^x \, dx$

you'll need to perform parts twice.

**Frggr** · October 27th 2010, 05:33 PM

Heh thanks. Realized my mistake. -- couldn't figure out
$integral(2^x)dx = v$
that you could sub
$let u = 2^x => ln(u) = xln(2)$
$dx/du = 1/uln(2)$

etc.

Was trying to:
$ln(v) = ln(integral(2^x)dx) = integral(ln(2^x)dx)$
which is just downright wrong.

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