Hi guys. I have a question regarding the epsilon-delta proof you provided, on example 3.

Here's a snippet:

Example 3. ....... we will replace |x+5| by a number M which satisfies |x+5| \leq M . In so doing, we rewrite as |x^2-25| < \epsilon \iff |x-5||x+5| < \epsilon \iff |x - 5|M < \epsilon \iff |x - 5| < \epsilon /M
and proceed as before taking \delta = \epsilon /M.

My question is regarding the M. If M is \geq |x+5|,
how do you conclude that |x+5||x-5| < \epsilon \iff |x-5|M < \epsilon.

I would think the opposite. Since M is greater than |x+5|, then |x-5|M might actually be greater than epsilon!

For example: let's say x=9, epsilon = 58, M = 15

so we get |14||4| = 56 < 58,
however, |4| times 15 = 60 > 58!

Hopefully, you understand what I'm trying to say. Can someone please help?

Thanks!