Find the area of region under the curve to the right of
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Originally Posted by viet Find the area of region under the curve to the right of You are looking for Hint: Put this in the denominator and use the substitution . Does this integral look more familiar? -Dan
Originally Posted by topsquark You are looking for Hint: Put this in the denominator and use the substitution . Does this integral look more familiar? -Dan Notice that 1/(x^2+x)=1/x-1/(x+1)
Last edited by curvature; Jun 20th 2007 at 12:47 PM.
Originally Posted by curvature Notice that 1/(x^2+x)=1/x-1/(x+1) the region looks like this
Originally Posted by curvature To viet: finally, you take the limit with , then it's done.
i got the final answer to be . thanks y'all
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