$\displaystyle \int (x^2-4x+4)^\frac{4}{3}dx$

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- Jun 20th 2007, 02:52 AM^_^Engineer_Adam^_^Integration help with u sub
$\displaystyle \int (x^2-4x+4)^\frac{4}{3}dx$

- Jun 20th 2007, 03:16 AMcurvature
u substitution:

- Jun 20th 2007, 03:27 AM^_^Engineer_Adam^_^
thanks

- Jun 20th 2007, 03:29 AMcurvature
Yes, it can be solved by u substitutuion.