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Math Help - indefinite integral

  1. #1
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    indefinite integral

    find the integral of 1/(t^3(t^2-1)^1/2))

    I tried this a multiple of times by treating u as secu. But somehow, the answer ends up as arctan something.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Taurus3 View Post
    find the integral of 1/(t^3(t^2-1)^1/2))

    I tried this a multiple of times by treating u as secu. But somehow, the answer ends up as arctan something.
    yeah, doing this via that trig sub will not get you arctan in your answer (that is the easier way to do this integral though, and if you do it correctly, your answer should be fine). they got their answer using trig sub twice. so if you insist on getting the answer your text got, proceed thusly (the harder way):

    Note that your integral is the same as:

    \displaystyle \int \frac t{t^4 (t^2 - 1)^{1/2}}~dt ............multiply by \displaystyle \frac tt

    Now, let \displaystyle u^2 = t^2 - 1, the integral becomes:

    \displaystyle \int \frac 1{(u^2 + 1)^2}~du

    \displaystyle = \int \frac {u^2 + 1 - u^2}{(u^2 + 1)^2}~du

    \displaystyle = \int \frac 1{u^2 + 1}~du - \int \frac {u^2}{(u^2 + 1)^2}~du

    The first integral will give you your arctan. For the second integral, use an appropriate trig sub.

    You should end up with the desired antiderivative.
    Last edited by Jhevon; October 22nd 2010 at 04:39 PM.
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