A mistake:
Ok so I did the derivative =
4x^3-2x y' + 4x^3 y' = 0
The derivative is:
A) Computer the tangent line to the curve x^4-yx^2+y^4 =1 at the point (-1,1)
Ok so I did the derivative =
4x^3-2x y' + 4x^3 y' = 0
Do I just take the point x (-1) put it in the formula for X to find y' and that's it? :S
B) Iterate Newton's method 2 times to produce a rational number approximating 4^-3. Use 2 as your initial guess.
Xn+1 = Xn - f(Xn)/(f'(Xn))
so... I'm lost about there :/