Ok.. I know that it comes out to be 10= (5b + 5b^2 -b^3)/b But I do not know how to solve for b.
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Originally Posted by Reefer Ok.. I know that it comes out to be 10= (5b + 5b^2 -b^3)/b But I do not know how to solve for b. You have: $\displaystyle -b^2+5b-5=0$ CB
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