Use Rolle's Theorem and argue the case that has at most one real root in the interval [-1,1]

Printable View

- Oct 21st 2010, 08:26 PMdrewbearRolle's Theorem!
Use Rolle's Theorem and argue the case that has at most one real root in the interval [-1,1]

- Oct 21st 2010, 08:44 PMJhevon
You can show it is possible to have a root using the intermediate value theorem.

To use Rolle's theorem to argue there is at most one, you can proceed thusly:

Assume, to the contrary, there are two roots (or more, but at least 2 is fine), say for and , both in the interval you are considering. and you may also assume that . then that means

and so according to Rolle's theorem, there must be a point , such that and .

Where can you get with that? - Oct 21st 2010, 09:12 PMdrewbear
i am sorry but i am still a little confused. i understand the IVT and the proving by contradiction, but the c variable is throwing me off. do i have to solve for that ever or is that just a constant of no importance?

- Oct 21st 2010, 09:50 PMTheEmptySet
c is a constant so when you take the derivative you get

As Jhevon suggested where are the zero's of ?