# Thread: Equation of the Tangent Line

1. ## Equation of the Tangent Line

Find the Equation of the tangent line for the curve:
at the point ( 3, 0.6 )

I already know the derivative is -4/25 but everytime I do it the answer comes out

y= -4/25 x +19/25 and I know that's wrong. Could someone please show me the work and the right answer???

Find the Equation of the tangent line for the curve:
at the point ( 3, 0.6 )

I already know the derivative is -4/25 but everytime I do it the answer comes out

y= -4/25 x +19/25 and I know that's wrong. Could someone please show me the work and the right answer???
why don't you show what you did and maybe someone can spot your mistake?

I already know the derivative is -4/25 but everytime I do it the answer comes out

Find the Equation of the tangent line for the curve:
at the point ( 3, 0.6 )

I already know the derivative is -4/25 but everytime I do it the answer comes out

y= -4/25 x +19/25 and I know that's wrong. Could someone please show me the work and the right answer???
You know that the tangent equation is in the form of y = mx + C where C is a constant.

Since you know the gradient, all you have to do is solve for C by substituting in your values.

Therefore you will have the equation:

$y = (\frac{-4}{25})x + C$

$0.6 = (\frac{-4}{25}) \times 3 + C$

$0.6 = -0.48 + C$

$0.6 + 0.48 = C$

$C = 1.08$

And so your equation will be: $y = (\frac{-4}{25}) x + 1.08$