Seems correct to me
You can simplify to:
T(x) = -1 -4x
Question: Find the tangent line to the graph of f(x) = 3 - 4e^x at x = 0.
My work:
dy/dx = -4e^x
Slope at x = 0 is m = -4
Tangent line equation:
T(x) = -1 - 4 (x - 0)
Is this correct?
Any help is appreciated