Calculate f'(x)

**Unknown008** · October 21st 2010, 10:09 AM

Like this:

$=e^{3x}\left(\dfrac{1}{cos^2x}+3tgx\right)$

Factoring and differentiating are different verbs

**Lil** · October 21st 2010, 10:20 AM

I'm awful at math and my English is bad too

. Thanks for help.

**Ackbeet** · October 21st 2010, 10:21 AM

You're very welcome for my contributions.

**Ackbeet** · October 21st 2010, 10:23 AM

If you're taking calculus, I wouldn't say you're all that terrible at math. A majority of people in the USA, at least, never take calculus, unfortunately.

**Lil** · October 21st 2010, 10:57 AM

$f(x)=e^{2\sqrt{x}}$
$f'(x)=(e^{2\sqrt{x}})'= (e^{2\sqrt{x}})' \cdot (2\sqrt{x})'= e^{2\sqrt{x}}\cdot \frac{1}{\sqrt{x}}= \frac{e^{2\sqrt{x}}}{\sqrt{x}}<br />$

I do it myself, so it's correct?

**Ackbeet** · October 21st 2010, 10:59 AM

Looks good to me. However, I would recommend not introducing a new problem this far into a thread. It won't get the visibility that a new thread will.

**Lil** · October 21st 2010, 11:02 AM

I know that...
Anyway, I'm so happy that I understood this task.

**Ackbeet** · October 21st 2010, 11:02 AM

Ok. Have a good one!

**Unknown008** · October 21st 2010, 11:05 AM

Correct!

EDIT: Oops, way way way too late =S

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