Like this:

$\displaystyle =e^{3x}\left(\dfrac{1}{cos^2x}+3tgx\right)$

Factoring and differentiating are different verbs (Wink)

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- Oct 21st 2010, 10:09 AMUnknown008
Like this:

$\displaystyle =e^{3x}\left(\dfrac{1}{cos^2x}+3tgx\right)$

Factoring and differentiating are different verbs (Wink) - Oct 21st 2010, 10:20 AMLil
I'm awful at math and my English is bad too (Worried). Thanks for help.

- Oct 21st 2010, 10:21 AMAckbeet
You're very welcome for my contributions.

- Oct 21st 2010, 10:23 AMAckbeet
If you're taking calculus, I wouldn't say you're all that terrible at math. A majority of people in the USA, at least, never take calculus, unfortunately.

- Oct 21st 2010, 10:57 AMLil
$\displaystyle f(x)=e^{2\sqrt{x}}$

$\displaystyle f'(x)=(e^{2\sqrt{x}})'= (e^{2\sqrt{x}})' \cdot (2\sqrt{x})'= e^{2\sqrt{x}}\cdot \frac{1}{\sqrt{x}}= \frac{e^{2\sqrt{x}}}{\sqrt{x}}

$

I do it myself, so it's correct? (Thinking) - Oct 21st 2010, 10:59 AMAckbeet
Looks good to me. However, I would recommend not introducing a new problem this far into a thread. It won't get the visibility that a new thread will.

- Oct 21st 2010, 11:02 AMLil
I know that...

Anyway, I'm so happy that I understood this task. (Clapping) - Oct 21st 2010, 11:02 AMAckbeet
Ok. Have a good one!

- Oct 21st 2010, 11:05 AMUnknown008
Correct! (Happy)

EDIT: Oops, way way way too late =S