# Calculate f'(x)

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• Oct 21st 2010, 11:09 AM
Unknown008
Like this:

$=e^{3x}\left(\dfrac{1}{cos^2x}+3tgx\right)$

Factoring and differentiating are different verbs (Wink)
• Oct 21st 2010, 11:20 AM
Lil
I'm awful at math and my English is bad too (Worried). Thanks for help.
• Oct 21st 2010, 11:21 AM
Ackbeet
You're very welcome for my contributions.
• Oct 21st 2010, 11:23 AM
Ackbeet
If you're taking calculus, I wouldn't say you're all that terrible at math. A majority of people in the USA, at least, never take calculus, unfortunately.
• Oct 21st 2010, 11:57 AM
Lil
$f(x)=e^{2\sqrt{x}}$
$f'(x)=(e^{2\sqrt{x}})'= (e^{2\sqrt{x}})' \cdot (2\sqrt{x})'= e^{2\sqrt{x}}\cdot \frac{1}{\sqrt{x}}= \frac{e^{2\sqrt{x}}}{\sqrt{x}}
$

I do it myself, so it's correct? (Thinking)
• Oct 21st 2010, 11:59 AM
Ackbeet
Looks good to me. However, I would recommend not introducing a new problem this far into a thread. It won't get the visibility that a new thread will.
• Oct 21st 2010, 12:02 PM
Lil
I know that...
Anyway, I'm so happy that I understood this task. (Clapping)
• Oct 21st 2010, 12:02 PM
Ackbeet
Ok. Have a good one!
• Oct 21st 2010, 12:05 PM
Unknown008
Correct! (Happy)

EDIT: Oops, way way way too late =S
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