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Math Help - Chain rule

  1. #1
    Junior Member
    Joined
    Jan 2010
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    43

    Exclamation Chain rule

    Hey,
    I am currently having difficulties applying the chain rule to problems from what i can gather the chain rule is the derivative of the inside multiplied by the derivative of the outside

    I tried working through a problem but screwed up somewhere,
    The problem
    find the derivative
    <br />
k(x)=x^{2}sec(\frac{1}{x})<br />

    what I did
    k(x)=x^{2}sec(\frac{1}{x})
    =  2x(secxtanx)\( \frac{x(0)-1(x)}{x})
    = 2x(secxtanx)(\frac{-1x}{x^{2}})
    = 2x(secxtanx)(\frac{-1}{x})
    = \frac{-2x(secx^{3})}{x}
    Am i on the right path
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  2. #2
    MHF Contributor Also sprach Zarathustra's Avatar
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    f(x)=x^2sec(\frac{1}{x})

    f'(x)=2xsec(\frac{1}{x})+x^2(sec(\frac{1}{x}))'

    (sec(\frac{1}{x})'=-{\frac{tan(frac{1}{x})sec(\frac{1}{x})}{x^2}}



    f'(x)=2xsec(\frac{1}{x})+x^2{\frac{tan(\frac{1}{x}  )sec(\frac{1}{x})}{x^2}}=2xsec(\frac{1}{x})-{{tan(\frac{1}{x})sec(\frac{1}{x})}
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