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Math Help - Work done?

  1. #1
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    Work done?

    Hello,
    please try to solve this question.
    Thanks
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by m777 View Post
    Hello,
    please try to solve this question.
    Thanks
    Why is this a problem?

    You have the parametric for fr the curve:

    <br />
\bold{r}(t) = \sin(t)\bold{i} + \cos(t)\bold{j} + \frac{t}{6}\bold{k}<br />

    and for the force:

    <br />
\bold{F}(x\bold{i}+y\bold{j}+x\bold{k}) = 6z \bold{i} + y^2 \bold{j} + 12x \bold{K} <br />

    so:

    <br />
\bold{F}(\bold{r}(t))= t\bold{i} + \cos^2(t)\bold{j}+12\sin(t)\bold{k} <br />

    and:

    <br />
\bold{dr}= \left( \cos(t)\bold{i}-\sin(t)\bold{j}+\frac{1}{6}\bold{k} \right) dt<br />

    Now you can write out the integral:

    <br />
\int_0^{2\pi} \bold{F}(\bold{r}(t)).\bold{dr}<br />

    explicitly, and it is a normal integral.

    RonL
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