Question: At t = 55 seconds, an object moving along a straight path is 47 meters from its origin. If the velocity at that time is v(55) = −3 meters per second, use a tangent line approximation to predict the objectís position at one minute (t = 60 seconds).
So I know that the equation for a tangent line is:
T(x) = f(x) + f'(x) (x-c)
But I am not sure if that is how I solve this question as I'm trying to predict the object's position.
Any help is appreciated.