Prove (x+1)^2 < or equal to 1 implies x< or equal to 0

Taking left hand side:

(x+1)^2 is less than or equal to 1

x^2 +2x < or equal to 0

So x(x+2) < or equal to 0.

If x =0, statemtn is true as 0.2 = 0

Is that accurate working out. How do I do the last step?!