I get stuck on this one.

$\displaystyle \displaystyle{ \int 8 x e^{2 x^2} \, dx}$

$\displaystyle

u=2x^2$

$\displaystyle du=4x$

$\displaystyle 8 \int 4x{e}^{u}$

$\displaystyle \frac{8}{4}\int du{e}^{u}$

$\displaystyle \frac{1}{2}\int du{e}^{u}$

My final answer was:

$\displaystyle \frac{1}{2}{e}^{2x^2}$

But I feel it's wrong.

This natural number always screws me up.