I understand how to do the part you just showed me. But how do find out it's negative? I graphed it, and it's negative on the interval (0, infinity). Is that right? I know that [0, inifinity) is wrong.
I understand how to do the part you just showed me. But how do find out it's negative? I graphed it, and it's negative on the interval (0, infinity). Is that right? I know that [0, inifinity) is wrong.
Based on the calculation above:f"(x) changes signs at x=-1/2.
the figures just visualize the result.
yeah, i know. i was just being nitpicky. i was in that kind of a mood. i'm bored to death right now. your figures definately helped. we may not be able to tell exactly what the inflection point is, but it does show that we could not be way off, which is good